What is ((x-7)^2)/(64)-((y-6)^2)/(36)=1 ?

The solution to ((x-7)^2)/(64)-((y-6)^2)/(36)=1 is Hyperbola with (h,k)=(7,6),a=8,b=6

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((x-7)^2)/(64)-((y-6)^2)/(36)=1

\frac{( x - 7 ) ^{2}}{64} - \frac{( y - 6 ) ^{2}}{36} = 1

(h, k) = (7, 6), a = 8, b = 6

Solution steps

\frac{( x - 7 ) ^{2}}{64} - \frac{( y - 6 ) ^{2}}{36} = 1

Rewrite

\frac{( x - 7 ) ^{2}}{64} - \frac{( y - 6 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - 7 ) ^{2}}{8 ^{2}} - \frac{( y - 6 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (7, 6), a = 8, b = 6

\frac{y ^{2}}{144} - \frac{x ^{2}}{25} = 1

25 y^{2} - x^{2} = 100

p^{2} + p = q^{2}

9 x^{2} - 4 y^{2} - 36 = 0

9 x^{2} - 16 y^{2} - 108 x + 128 y + 212 = 0

What is ((x-7)^2)/(64)-((y-6)^2)/(36)=1 ?
The solution to ((x-7)^2)/(64)-((y-6)^2)/(36)=1 is Hyperbola with (h,k)=(7,6),a=8,b=6