What is 16x^2-9y^2-96x+288=0 ?

The solution to 16x^2-9y^2-96x+288=0 is Hyperbola with (h,k)=(3,0),a=4,b=3

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16x^2-9y^2-96x+288=0

16 x^{2} - 9 y^{2} - 96 x + 288 = 0

(h, k) = (3, 0), a = 4, b = 3

Solution steps

16 x^{2} - 9 y^{2} - 96 x + 288 = 0

Rewrite

16 x^{2} - 9 y^{2} - 96 x + 288 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 3 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 0), a = 4, b = 3

\frac{( x + 4 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{4} = 1

24 x^{2} - 9 y^{2} = 216

4 x^{2} - 6 y^{2} = 9

4 x^{2} - 2 x - 4 y^{2} - 4 = 0

3 x^{2} - y^{2} = 3

What is 16x^2-9y^2-96x+288=0 ?
The solution to 16x^2-9y^2-96x+288=0 is Hyperbola with (h,k)=(3,0),a=4,b=3