What is y^2-16x^2+64x-208=0 ?

The solution to y^2-16x^2+64x-208=0 is Hyperbola with (h,k)=(2,0),a=12,b=3

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y^2-16x^2+64x-208=0

y^{2} - 16 x^{2} + 64 x - 208 = 0

(h, k) = (2, 0), a = 12, b = 3

Solution steps

y^{2} - 16 x^{2} + 64 x - 208 = 0

Rewrite

y^{2} - 16 x^{2} + 64 x - 208 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{1 2 ^{2}} - \frac{( x - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 0), a = 12, b = 3

9 x^{2} - 9 y^{2} - 18 x + 54 = 0

y^{2} - 4 x^{2} + 16 x - 2 y = 31

(3 y + 3)^{2} + x = (x - 4)^{2}

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

- y^{2} + z^{2} = 1

What is y^2-16x^2+64x-208=0 ?
The solution to y^2-16x^2+64x-208=0 is Hyperbola with (h,k)=(2,0),a=12,b=3