What is 4x^2-y^2-8x-4y-4=0 ?

The solution to 4x^2-y^2-8x-4y-4=0 is Hyperbola with (h,k)=(1,-2),a=1,b=2

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4x^2-y^2-8x-4y-4=0

4 x^{2} - y^{2} - 8 x - 4 y - 4 = 0

(h, k) = (1, - 2), a = 1, b = 2

Solution steps

4 x^{2} - y^{2} - 8 x - 4 y - 4 = 0

Rewrite

4 x^{2} - y^{2} - 8 x - 4 y - 4 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{1 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 1, b = 2

\frac{y ^{2}}{64} - \frac{x ^{2}}{9} = 1

x^{2} - y^{2} = 105

x^{2} - y^{2} - (- 10) = 0

\frac{( x - 2 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

9 x^{2} - y^{2} - 18 x + 10 y - 52 = 0

What is 4x^2-y^2-8x-4y-4=0 ?
The solution to 4x^2-y^2-8x-4y-4=0 is Hyperbola with (h,k)=(1,-2),a=1,b=2