What is 16x^2-25y^2-32x+100y-484=0 ?

The solution to 16x^2-25y^2-32x+100y-484=0 is Hyperbola with (h,k)=(1,2),a=5,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16x^2-25y^2-32x+100y-484=0

16 x^{2} - 25 y^{2} - 32 x + 100 y - 484 = 0

(h, k) = (1, 2), a = 5, b = 4

Solution steps

16 x^{2} - 25 y^{2} - 32 x + 100 y - 484 = 0

Rewrite

16 x^{2} - 25 y^{2} - 32 x + 100 y - 484 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{5 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 5, b = 4

x, h (x)^{2} = x^{2} + 5 x

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

x^{2} - 3 y^{2} + 5 y = 7

3 x^{2} - 5 y^{2} + y = 2

x^{2} - 2 y^{2} = 8

What is 16x^2-25y^2-32x+100y-484=0 ?
The solution to 16x^2-25y^2-32x+100y-484=0 is Hyperbola with (h,k)=(1,2),a=5,b=4