What is (2x^2)/(25)-((y-3)^2)/(49)=1 ?

The solution to (2x^2)/(25)-((y-3)^2)/(49)=1 is Hyperbola with (h,k)=(0,3),a= 5/(sqrt(2)),b=7

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(2x^2)/(25)-((y-3)^2)/(49)=1

\frac{2 x ^{2}}{25} - \frac{( y - 3 ) ^{2}}{49} = 1

(h, k) = (0, 3), a = \frac{5}{2}, b = 7

Solution steps

\frac{2 x ^{2}}{25} - \frac{( y - 3 ) ^{2}}{49} = 1

Rewrite

\frac{2 x ^{2}}{25} - \frac{( y - 3 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} - \frac{( y - 3 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 3), a = \frac{5}{2}, b = 7

9 x^{2} - y^{2} - 54 x + 45 = 0

3 y^{2} - 4 x^{2} - 6 y - 24 x - 105 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{13} = 1

x, 4 k (x)^{2} - 4 x (x + 1) = 7

x^{2} - \frac{y ^{2}}{25} = 1

What is (2x^2)/(25)-((y-3)^2)/(49)=1 ?
The solution to (2x^2)/(25)-((y-3)^2)/(49)=1 is Hyperbola with (h,k)=(0,3),a= 5/(sqrt(2)),b=7