What is 2y^2-x^2+2x+8y+3=0 ?

The solution to 2y^2-x^2+2x+8y+3=0 is Hyperbola with (h,k)=(1,-2),a=sqrt(2),b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2y^2-x^2+2x+8y+3=0

2 y^{2} - x^{2} + 2 x + 8 y + 3 = 0

(h, k) = (1, - 2), a = 2, b = 2

Solution steps

2 y^{2} - x^{2} + 2 x + 8 y + 3 = 0

Rewrite

2 y^{2} - x^{2} + 2 x + 8 y + 3 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{( 2 ) ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 2, b = 2

25 x^{2} - 100 x - 9 y^{2} + 18 y + 316 = 0

\frac{y ^{2}}{1} - \frac{x ^{2}}{16} = 1

x^{2} - 8 x - y^{2} - 10 y - 36 = 0

x^{2} - 2 y^{2} + 3 x + 4 y = 2

z^{2} - y^{2} = 1

What is 2y^2-x^2+2x+8y+3=0 ?
The solution to 2y^2-x^2+2x+8y+3=0 is Hyperbola with (h,k)=(1,-2),a=sqrt(2),b=2