What is x^2-3y^2+8x-6y+4=0 ?

The solution to x^2-3y^2+8x-6y+4=0 is Hyperbola with (h,k)=(-4,-1),a=3,b=sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-3y^2+8x-6y+4=0

x^{2} - 3 y^{2} + 8 x - 6 y + 4 = 0

(h, k) = (- 4, - 1), a = 3, b = 3

Solution steps

x^{2} - 3 y^{2} + 8 x - 6 y + 4 = 0

Rewrite

x^{2} - 3 y^{2} + 8 x - 6 y + 4 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 1), a = 3, b = 3

x^{2} = 16 + y^{2}

e^{l n (y^{2} + 2)} = e^{l n (x^{2} + 4)}

144 x^{2} - 25 y^{2} = 169

3 x^{2} - 4 y^{2} + 16 y - 18 = 0

\frac{x ^{2}}{1} - \frac{y ^{2}}{4} = 1

What is x^2-3y^2+8x-6y+4=0 ?
The solution to x^2-3y^2+8x-6y+4=0 is Hyperbola with (h,k)=(-4,-1),a=3,b=sqrt(3)