What is (x^2)/(16)-(y^2)/(12)=1 ?

The solution to (x^2)/(16)-(y^2)/(12)=1 is Hyperbola with (h,k)=(0,0),a=4,b=2sqrt(3)

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(x^2)/(16)-(y^2)/(12)=1

\frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

(h, k) = (0, 0), a = 4, b = 23

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 23

3 x^{2} - 2 y^{2} - 12 x + 12 y + 29 = 0

9 x^{2} - 4 y^{2} + 36 x + 8 y + 33 = 0

(x - 5)^{2} - (y - 4)^{2} = 1

144 x^{2} - 25 y^{2} + 864 x - 100 y - 2404 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

What is (x^2)/(16)-(y^2)/(12)=1 ?
The solution to (x^2)/(16)-(y^2)/(12)=1 is Hyperbola with (h,k)=(0,0),a=4,b=2sqrt(3)