What is ((x+1)/(25))^2-((y-4)/(144))^2=1 ?

The solution to ((x+1)/(25))^2-((y-4)/(144))^2=1 is Hyperbola with (h,k)=(-1,4),a=25,b=144

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((x+1)/(25))^2-((y-4)/(144))^2=1

(\frac{x + 1}{25})^{2} - (\frac{y - 4}{144})^{2} = 1

(h, k) = (- 1, 4), a = 25, b = 144

Solution steps

(\frac{x + 1}{25})^{2} - (\frac{y - 4}{144})^{2} = 1

Rewrite

(\frac{x + 1}{25})^{2} - (\frac{y - 4}{144})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{2 5 ^{2}} - \frac{( y - 4 ) ^{2}}{14 4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 25, b = 144

\frac{x ^{2}}{64} - \frac{y ^{2}}{100} = 1

y^{2} = (x - 2)^{2} - 1

y^{2} - x^{2} = 100

y^{2} - x^{2} + 5 x - 4 y + 3 = 0

\frac{( x + 2 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{25} = 1

What is ((x+1)/(25))^2-((y-4)/(144))^2=1 ?
The solution to ((x+1)/(25))^2-((y-4)/(144))^2=1 is Hyperbola with (h,k)=(-1,4),a=25,b=144