What is (x^2)/5-(y^2)/4 =1 ?

The solution to (x^2)/5-(y^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=sqrt(5),b=2

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(x^2)/5-(y^2)/4 =1

\frac{x ^{2}}{5} - \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 5, b = 2

Solution steps

\frac{x ^{2}}{5} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{5} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 2

y^{2} = 4 + z^{2} - 2 z

a^{2} - b^{2} = 51

10 y^{2} - 9 x^{2} = 144

10 x^{2} - 7 y^{2} - 30 x + 14 y = 5

25 x^{2} - 9 y^{2} + 100 x - 54 y + 10 = 0

What is (x^2)/5-(y^2)/4 =1 ?
The solution to (x^2)/5-(y^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=sqrt(5),b=2