What is the foci (x^2}{16}-\frac{y^2)/9 =1 ?

The foci (x^2}{16}-\frac{y^2)/9 =1 is (5,0),(-5,0)

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foci (x^2}{16}-\frac{y^2)/9 =1

foci

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} + 3^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

x^{2} - 12 x + 16 y + 68 = 0

10 x^{2} + 4 y^{2} + 2 x + 16 y = 144

y^{2} = - 36 x

x^{2} = 4 y

f (x) = x^{2} - 9

What is the foci (x^2}{16}-\frac{y^2)/9 =1 ?
The foci (x^2}{16}-\frac{y^2)/9 =1 is (5,0),(-5,0)