What is ((y-4)^2)/(36)-((x-1)^2)/(16)=1 ?

The solution to ((y-4)^2)/(36)-((x-1)^2)/(16)=1 is Hyperbola with (h,k)=(1,4),a=6,b=4

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((y-4)^2)/(36)-((x-1)^2)/(16)=1

\frac{( y - 4 ) ^{2}}{36} - \frac{( x - 1 ) ^{2}}{16} = 1

(h, k) = (1, 4), a = 6, b = 4

Solution steps

\frac{( y - 4 ) ^{2}}{36} - \frac{( x - 1 ) ^{2}}{16} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{36} - \frac{( x - 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{6 ^{2}} - \frac{( x - 1 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 4), a = 6, b = 4

- 16 x^{2} + y^{2} + 128 x + 2 y - 271 = 0

x^{2} - 36 y^{2} = 36

x^{2} - 4 y^{2} - 64 = 0

2 x^{2} - y^{2} = 1

9 y^{2} - 16 x^{2} = 1296

What is ((y-4)^2)/(36)-((x-1)^2)/(16)=1 ?
The solution to ((y-4)^2)/(36)-((x-1)^2)/(16)=1 is Hyperbola with (h,k)=(1,4),a=6,b=4