What is -3x^2+y^2=2 ?

The solution to -3x^2+y^2=2 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=sqrt(2/3)

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-3x^2+y^2=2

- 3 x^{2} + y^{2} = 2

(h, k) = (0, 0), a = 2, b = \frac{2}{3}

Solution steps

- 3 x^{2} + y^{2} = 2

Rewrite

- 3 x^{2} + y^{2} = 2

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{2}{3} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = \frac{2}{3}

\frac{x ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

x^{2} - z^{2} + 24 = 0

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0

\frac{( x ^{2} )}{4} - \frac{( y ^{2} )}{9} = 1

\frac{( x - 2 ) ^{2}}{16} - \frac{( y + 1 ) ^{2}}{9} = 1

What is -3x^2+y^2=2 ?
The solution to -3x^2+y^2=2 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=sqrt(2/3)