What is 16y^2-4x^2-24x-12y-34=0 ?

The solution to 16y^2-4x^2-24x-12y-34=0 is Hyperbola with (h,k)=(-3, 3/8),a= 1/8 ,b= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16y^2-4x^2-24x-12y-34=0

16 y^{2} - 4 x^{2} - 24 x - 12 y - 34 = 0

(h, k) = (- 3, \frac{3}{8}), a = \frac{1}{8}, b = \frac{1}{4}

Solution steps

16 y^{2} - 4 x^{2} - 24 x - 12 y - 34 = 0

Rewrite

16 y^{2} - 4 x^{2} - 24 x - 12 y - 34 = 0

in the form of a standard hyperbola equation

\frac{( y - \frac{3}{8} ) ^{2}}{( \frac{1}{8} ) ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{( \frac{1}{4} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, \frac{3}{8}), a = \frac{1}{8}, b = \frac{1}{4}

x^{2} + x - y^{2} = 5

(x - 8)^{2} - (y + 6)^{2} = 1

4 y^{2} - 2 x^{2} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1

\frac{( x - 6 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{25} = 1

What is 16y^2-4x^2-24x-12y-34=0 ?
The solution to 16y^2-4x^2-24x-12y-34=0 is Hyperbola with (h,k)=(-3, 3/8),a= 1/8 ,b= 1/4