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y^2=x-3

الحلّ

y^{2} = x - 3

الحلّ

(h, k) = (3, 0), p = \frac{1}{4}

خطوات الحلّ

y^{2} = x - 3

Rewrite

y^{2} = x - 3

in the standard form:

4 \cdot \frac{1}{4} (x - 3) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = \frac{1}{4}

أمثلة شائعة

((x-5)^2}{25}+\frac{(y+3)^2)/9 =1

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1

foci 16y^2-25x^2=400 foci

16 y^{2} - 25 x^{2} = 400

eccentricity 16x^2+25y^2=400 eccentricity

16 x^{2} + 25 y^{2} = 400

x^{2} + y^{2} = 25

(x^2)/(64)+(y^2)/(36)=1

\frac{x ^{2}}{64} + \frac{y ^{2}}{36} = 1