What is ((x+1)^2)/(25)-((y-2)^2)/(16)=1 ?

The solution to ((x+1)^2)/(25)-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(-1,2),a=5,b=4

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((x+1)^2)/(25)-((y-2)^2)/(16)=1

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

(h, k) = (- 1, 2), a = 5, b = 4

Solution steps

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 5, b = 4

y^{2} = (x - 4)^{2} - 1

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

3 x^{2} - 3 y^{2} = 2 y

16 x^{2} - 9 y^{2} - 90 y - 369 = 0

y^{2} - z^{2} + 2 z - 4 = 0

What is ((x+1)^2)/(25)-((y-2)^2)/(16)=1 ?
The solution to ((x+1)^2)/(25)-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(-1,2),a=5,b=4