What is ((y+2)^2}{25}-\frac{(x-6)^2)/9 =1 ?

The solution to ((y+2)^2}{25}-\frac{(x-6)^2)/9 =1 is Hyperbola with (h,k)=(6,-2),a=5,b=3

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((y+2)^2}{25}-\frac{(x-6)^2)/9 =1

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{9} = 1

(h, k) = (6, - 2), a = 5, b = 3

Solution steps

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{9} = 1

Rewrite

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 6 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{5 ^{2}} - \frac{( x - 6 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, - 2), a = 5, b = 3

5 y^{2} + 30 y + 8 x - 79 - 4 x^{2} = 0

4 x^{2} - y^{2} - 24 x - 4 y + 16 = 0

\frac{( y - 1 ) ^{2}}{49} - \frac{( x - 2 ) ^{2}}{32} = 1

4 x^{2} + 8 x - 3 y^{2} + 16 = 0

f (x) (f (x)) = x^{2} + 1

What is ((y+2)^2}{25}-\frac{(x-6)^2)/9 =1 ?
The solution to ((y+2)^2}{25}-\frac{(x-6)^2)/9 =1 is Hyperbola with (h,k)=(6,-2),a=5,b=3