What is -(36(x-3)^2)/1+(25(y-4)^2)/1 =900 ?

The solution to -(36(x-3)^2)/1+(25(y-4)^2)/1 =900 is Hyperbola with (h,k)=(3,4),a=6,b=5

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-(36(x-3)^2)/1+(25(y-4)^2)/1 =900

- \frac{36 ( x - 3 ) ^{2}}{1} + \frac{25 ( y - 4 ) ^{2}}{1} = 900

(h, k) = (3, 4), a = 6, b = 5

Solution steps

- \frac{36 ( x - 3 ) ^{2}}{1} + \frac{25 ( y - 4 ) ^{2}}{1} = 900

Rewrite

- \frac{36 ( x - 3 ) ^{2}}{1} + \frac{25 ( y - 4 ) ^{2}}{1} = 900

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{6 ^{2}} - \frac{( x - 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 4), a = 6, b = 5

x^{2} - 5 y^{2} = 3

\frac{( y + 5 ) ^{2}}{100} - \frac{( x - 4 ) ^{2}}{121} = 1

1 0^{2} + x^{2} = y^{2}

8 y^{2} - x^{2} - 16 y + 8 x - 16 = 0

9 x^{2} + 36 x - 4 y^{2} - 16 y - 16 = 0

What is -(36(x-3)^2)/1+(25(y-4)^2)/1 =900 ?
The solution to -(36(x-3)^2)/1+(25(y-4)^2)/1 =900 is Hyperbola with (h,k)=(3,4),a=6,b=5