What is (x^2)/(20^2)-(y^2)/(15^2)=1 ?

The solution to (x^2)/(20^2)-(y^2)/(15^2)=1 is Hyperbola with (h,k)=(0,0),a=20,b=15

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(x^2)/(20^2)-(y^2)/(15^2)=1

\frac{x ^{2}}{2 0 ^{2}} - \frac{y ^{2}}{1 5 ^{2}} = 1

(h, k) = (0, 0), a = 20, b = 15

Solution steps

\frac{x ^{2}}{2 0 ^{2}} - \frac{y ^{2}}{1 5 ^{2}} = 1

Rewrite

\frac{x ^{2}}{2 0 ^{2}} - \frac{y ^{2}}{1 5 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 0 ^{2}} - \frac{( y - 0 ) ^{2}}{1 5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 20, b = 15

7 y^{2} - 14 x^{2} = 98

(\frac{x ^{2}}{36}) - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

- 4 x^{2} + 5 y^{2} + 8 x - 30 y + 21 = 0

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

What is (x^2)/(20^2)-(y^2)/(15^2)=1 ?
The solution to (x^2)/(20^2)-(y^2)/(15^2)=1 is Hyperbola with (h,k)=(0,0),a=20,b=15