What is -3x^2+y^2-12=0 ?

The solution to -3x^2+y^2-12=0 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=2

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-3x^2+y^2-12=0

- 3 x^{2} + y^{2} - 12 = 0

(h, k) = (0, 0), a = 23, b = 2

Solution steps

- 3 x^{2} + y^{2} - 12 = 0

Rewrite

- 3 x^{2} + y^{2} - 12 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 2 3 ) ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 23, b = 2

y^{2} = 4 x^{2} + 3 x + 2

(\frac{( y + 1 ) ^{2}}{( 1 )}) - (\frac{( x + 1 ) ^{2}}{( 1 )}) = 1

\frac{v ^{2}}{2} = 2 s^{2} - 0.02

4 x^{2} - 9 y^{2} = 144

x^{2} - 3 y^{2} - 3 x = 4 y + 5

What is -3x^2+y^2-12=0 ?
The solution to -3x^2+y^2-12=0 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=2