What is (x^2)/(49)-((y+2)^2)/(79)=1 ?

The solution to (x^2)/(49)-((y+2)^2)/(79)=1 is Hyperbola with (h,k)=(0,-2),a=7,b=sqrt(79)

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(x^2)/(49)-((y+2)^2)/(79)=1

\frac{x ^{2}}{49} - \frac{( y + 2 ) ^{2}}{79} = 1

(h, k) = (0, - 2), a = 7, b = 79

Solution steps

\frac{x ^{2}}{49} - \frac{( y + 2 ) ^{2}}{79} = 1

Rewrite

\frac{x ^{2}}{49} - \frac{( y + 2 ) ^{2}}{79} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{( 79 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 2), a = 7, b = 79

- \frac{x ^{2}}{144} + \frac{y ^{2}}{25} = 1

\frac{( x - 4 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{25} = 1

y^{2} = \frac{4 x ^{2}}{9} - 9

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 1 ) ^{2}}{16} = 1

\frac{( y - \frac{1}{4} ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

What is (x^2)/(49)-((y+2)^2)/(79)=1 ?
The solution to (x^2)/(49)-((y+2)^2)/(79)=1 is Hyperbola with (h,k)=(0,-2),a=7,b=sqrt(79)