What is (x^2)/(16)-(y^2)/(33)=1 ?

The solution to (x^2)/(16)-(y^2)/(33)=1 is Hyperbola with (h,k)=(0,0),a=4,b=sqrt(33)

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(x^2)/(16)-(y^2)/(33)=1

\frac{x ^{2}}{16} - \frac{y ^{2}}{33} = 1

(h, k) = (0, 0), a = 4, b = 33

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{33} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{33} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{( 33 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 33

6 x^{2} - 5 y^{2} + 12 x - 30 y - 9 = 0

18 y^{2} - 4 x^{2} = 1

1 1^{2} - x^{2} + y^{2} = 9^{2}

9 (x - 3)^{2} - 4 (y - 1)^{2} = - 36

x^{2} - y^{2} - 2 x - 2 y - 1 = 0

What is (x^2)/(16)-(y^2)/(33)=1 ?
The solution to (x^2)/(16)-(y^2)/(33)=1 is Hyperbola with (h,k)=(0,0),a=4,b=sqrt(33)