What is (x^2)/8-(y^2)/(64)=1 ?

The solution to (x^2)/8-(y^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=8

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(x^2)/8-(y^2)/(64)=1

\frac{x ^{2}}{8} - \frac{y ^{2}}{64} = 1

(h, k) = (0, 0), a = 22, b = 8

Solution steps

\frac{x ^{2}}{8} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{8} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 22, b = 8

2 x 4 x + (- 2) y 4 y = - 200

x = \frac{5 x ^{2} - 5 y ^{2}}{2}

- 3 x^{2} + 2 y^{2} + 18 x - 20 y + 17 = 0

\frac{x ^{2}}{8 ^{2}} - \frac{y ^{2}}{5 ^{2}} = 1

4 y^{2} - x^{2} + 16 y + 12 = 0

What is (x^2)/8-(y^2)/(64)=1 ?
The solution to (x^2)/8-(y^2)/(64)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=8