What is x^2-y^2-4x+3=0 ?

The solution to x^2-y^2-4x+3=0 is Hyperbola with (h,k)=(2,0),a=1,b=1

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x^2-y^2-4x+3=0

x^{2} - y^{2} - 4 x + 3 = 0

(h, k) = (2, 0), a = 1, b = 1

Solution steps

x^{2} - y^{2} - 4 x + 3 = 0

Rewrite

x^{2} - y^{2} - 4 x + 3 = 0

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 0), a = 1, b = 1

1 + y^{2} = x^{2} (\frac{10}{4})

(\frac{x ^{2}}{16}) - (\frac{( y + 4 ) ^{2}}{81}) = 1

16 x^{2} + 96 x - 9 y^{2} + 54 y + 207 = 0

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

- y^{2} + x^{2} + 26 y - 26 x = - 121

What is x^2-y^2-4x+3=0 ?
The solution to x^2-y^2-4x+3=0 is Hyperbola with (h,k)=(2,0),a=1,b=1