What is ((x^2)/(16))-(((y+4)^2)/(81))=1 ?

The solution to ((x^2)/(16))-(((y+4)^2)/(81))=1 is Hyperbola with (h,k)=(0,-4),a=4,b=9

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((x^2)/(16))-(((y+4)^2)/(81))=1

(\frac{x ^{2}}{16}) - (\frac{( y + 4 ) ^{2}}{81}) = 1

(h, k) = (0, - 4), a = 4, b = 9

Solution steps

\frac{x ^{2}}{16} - \frac{( y + 4 ) ^{2}}{81} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{( y + 4 ) ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - ( - 4 ) ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 4), a = 4, b = 9

16 x^{2} + 96 x - 9 y^{2} + 54 y + 207 = 0

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

- y^{2} + x^{2} + 26 y - 26 x = - 121

(y + 2)^{2} - 25 (x - 2)^{2} = 25

x, x^{2} - x + 1 - 2 k (x)^{2} + 4 k + 1 = 0

What is ((x^2)/(16))-(((y+4)^2)/(81))=1 ?
The solution to ((x^2)/(16))-(((y+4)^2)/(81))=1 is Hyperbola with (h,k)=(0,-4),a=4,b=9