What is ((x-2.5)^2)/(2.5^2)-((y-5)^2)/(5^2)=1 ?

The solution to ((x-2.5)^2)/(2.5^2)-((y-5)^2)/(5^2)=1 is Hyperbola with (h,k)=(2.5,5),a=2.5,b=5

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((x-2.5)^2)/(2.5^2)-((y-5)^2)/(5^2)=1

\frac{( x - 2.5 ) ^{2}}{2. 5 ^{2}} - \frac{( y - 5 ) ^{2}}{5 ^{2}} = 1

(h, k) = (2.5, 5), a = 2.5, b = 5

Solution steps

\frac{( x - 2.5 ) ^{2}}{2. 5 ^{2}} - \frac{( y - 5 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2.5, 5), a = 2.5, b = 5

x^{2} - 2 y^{2} = - 1

2 x^{2} - 2 y^{2} - 20 x + 16 y - 16 = 0

x^{2} + 4 x - y^{2} = 0

(x + 5)^{2} - (y - 7)^{2} = 1

\frac{1}{2} y^{2} - 2 y = \frac{3}{2} x^{2} - 5 x

What is ((x-2.5)^2)/(2.5^2)-((y-5)^2)/(5^2)=1 ?
The solution to ((x-2.5)^2)/(2.5^2)-((y-5)^2)/(5^2)=1 is Hyperbola with (h,k)=(2.5,5),a=2.5,b=5