What is ((x+3)^2)/9-((y-1)^2)/4 =1 ?

The solution to ((x+3)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(-3,1),a=3,b=2

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((x+3)^2)/9-((y-1)^2)/4 =1

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

(h, k) = (- 3, 1), a = 3, b = 2

Solution steps

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 1), a = 3, b = 2

(\frac{K ( x )}{2})^{2} = 4096 + 4096 - 128 x + x^{2}

1 \cdot 3 = (a + b) (a - b)

x^{2} - y^{2} = - (1)

x, 2 x^{2} - 28 x + 196 = r (x)^{2}

- x^{2} + y^{2} = - 11

What is ((x+3)^2)/9-((y-1)^2)/4 =1 ?
The solution to ((x+3)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(-3,1),a=3,b=2