What is ((y-5)^2)/4-((x-2)^2)/(12)=1 ?

The solution to ((y-5)^2)/4-((x-2)^2)/(12)=1 is Hyperbola with (h,k)=(2,5),a=2,b=2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-5)^2)/4-((x-2)^2)/(12)=1

\frac{( y - 5 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{12} = 1

(h, k) = (2, 5), a = 2, b = 23

Solution steps

\frac{( y - 5 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{12} = 1

Rewrite

\frac{( y - 5 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{12} = 1

in the form of a standard hyperbola equation

\frac{( y - 5 ) ^{2}}{2 ^{2}} - \frac{( x - 2 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 5), a = 2, b = 23

3 x^{2} - 5 y^{2} + 6 x + 10 = 32

8 y^{2} - 2 x^{2} = 16

y^{2} = 100 + x^{2}

x^{(2)} - 2 x - 4 y^{(2)} + 24 y = 31

x + 2 y^{2} - 2 x y = 2 x^{2} - 2 x y - x^{2}

What is ((y-5)^2)/4-((x-2)^2)/(12)=1 ?
The solution to ((y-5)^2)/4-((x-2)^2)/(12)=1 is Hyperbola with (h,k)=(2,5),a=2,b=2sqrt(3)