What is x^2-y^2+7x+8y-5=0 ?

The solution to x^2-y^2+7x+8y-5=0 is Hyperbola with (h,k)=(-7/2 ,4),a=(sqrt(5))/2 ,b=(sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-y^2+7x+8y-5=0

x^{2} - y^{2} + 7 x + 8 y - 5 = 0

(h, k) = (- \frac{7}{2}, 4), a = \frac{5}{2}, b = \frac{5}{2}

Solution steps

x^{2} - y^{2} + 7 x + 8 y - 5 = 0

Rewrite

x^{2} - y^{2} + 7 x + 8 y - 5 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - \frac{7}{2} ) ) ^{2}}{( \frac{5}{2} ) ^{2}} - \frac{( y - 4 ) ^{2}}{( \frac{5}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- \frac{7}{2}, 4), a = \frac{5}{2}, b = \frac{5}{2}

\frac{( y - 1 ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

2 x^{2} - 4 y^{2} + 12 x + 8 y + 10 = 0

\frac{x ^{2}}{11} - \frac{y ^{2}}{16} = 1

x^{(2)} - y^{(2)} = 4

5 x^{2} - 3 y^{2} = 8

What is x^2-y^2+7x+8y-5=0 ?
The solution to x^2-y^2+7x+8y-5=0 is Hyperbola with (h,k)=(-7/2 ,4),a=(sqrt(5))/2 ,b=(sqrt(5))/2