What is 3y^2-x^2+6x-12=0 ?

The solution to 3y^2-x^2+6x-12=0 is Hyperbola with (h,k)=(3,0),a=1,b=sqrt(3)

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3y^2-x^2+6x-12=0

3 y^{2} - x^{2} + 6 x - 12 = 0

(h, k) = (3, 0), a = 1, b = 3

Solution steps

3 y^{2} - x^{2} + 6 x - 12 = 0

Rewrite

3 y^{2} - x^{2} + 6 x - 12 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( x - 3 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 0), a = 1, b = 3

- \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{1 ^{2}} - \frac{z ^{2}}{2 ^{2}} = 1

x^{2} - 4 y^{2} + 2 x - 32 y - 67 = 0

\frac{x ^{2} - y ^{2}}{3} = 1

\frac{( y - 4 ) ^{2}}{100} - \frac{( x - 7 ) ^{2}}{49} = 1

What is 3y^2-x^2+6x-12=0 ?
The solution to 3y^2-x^2+6x-12=0 is Hyperbola with (h,k)=(3,0),a=1,b=sqrt(3)