What is (x^2)/3-((y+1)^2)/3 =1 ?

The solution to (x^2)/3-((y+1)^2)/3 =1 is Hyperbola with (h,k)=(0,-1),a=sqrt(3),b=sqrt(3)

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(x^2)/3-((y+1)^2)/3 =1

\frac{x ^{2}}{3} - \frac{( y + 1 ) ^{2}}{3} = 1

(h, k) = (0, - 1), a = 3, b = 3

Solution steps

\frac{x ^{2}}{3} - \frac{( y + 1 ) ^{2}}{3} = 1

Rewrite

\frac{x ^{2}}{3} - \frac{( y + 1 ) ^{2}}{3} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 1), a = 3, b = 3

9 x^{2} - 4 y^{2} + 18 x - 16 y - 43 = 0

8 x^{2} - 5 y^{2} + 96 x + 40 y + 168 = 0

\frac{x ^{2}}{121} - \frac{y ^{2}}{9} = 1

5 x^{2} - y^{2} = 20

(y - 3)^{2} - 9 (x - 3)^{2} = 9

What is (x^2)/3-((y+1)^2)/3 =1 ?
The solution to (x^2)/3-((y+1)^2)/3 =1 is Hyperbola with (h,k)=(0,-1),a=sqrt(3),b=sqrt(3)