What is (x^2}{12}-\frac{y^2)/4 =1 ?

The solution to (x^2}{12}-\frac{y^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=2

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(x^2}{12}-\frac{y^2)/4 =1

\frac{x ^{2}}{12} - \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 23, b = 2

Solution steps

\frac{x ^{2}}{12} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{12} - \frac{y ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 3 ) ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 23, b = 2

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{25} = 1

x^{2} - y^{2} + 6 x + 2 y = 6

3 x^{2} - y^{2} + 18 x + 8 y + 38 = 0

0 = 1 + y^{2} - x^{2}

y^{2} = x^{2} + 12 x + 32

What is (x^2}{12}-\frac{y^2)/4 =1 ?
The solution to (x^2}{12}-\frac{y^2)/4 =1 is Hyperbola with (h,k)=(0,0),a=2sqrt(3),b=2