What is 4(x+1)^2-3(y-2)^2=15 ?

The solution to 4(x+1)^2-3(y-2)^2=15 is Hyperbola with (h,k)=(-1,2),a=(sqrt(15))/2 ,b=sqrt(5)

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4(x+1)^2-3(y-2)^2=15

4 (x + 1)^{2} - 3 (y - 2)^{2} = 15

(h, k) = (- 1, 2), a = \frac{15}{2}, b = 5

Solution steps

4 (x + 1)^{2} - 3 (y - 2)^{2} = 15

Rewrite

4 (x + 1)^{2} - 3 (y - 2)^{2} = 15

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{( \frac{15}{2} ) ^{2}} - \frac{( y - 2 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = \frac{15}{2}, b = 5

4 x^{2} - 3 y^{2} + 8 x + 16 = 0

(x + 5)^{2} - (y + 6)^{2} = 20

- x^{2} + 2 y^{2} = 1

\frac{x ^{2}}{100} - \frac{y ^{2}}{75} = 1

64 x^{2} - 36 y^{2} + 192 x + 36 y - 441 = 0

What is 4(x+1)^2-3(y-2)^2=15 ?
The solution to 4(x+1)^2-3(y-2)^2=15 is Hyperbola with (h,k)=(-1,2),a=(sqrt(15))/2 ,b=sqrt(5)