What is 8x^2-15=4y^2+1 ?

The solution to 8x^2-15=4y^2+1 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=2

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8x^2-15=4y^2+1

8 x^{2} - 15 = 4 y^{2} + 1

(h, k) = (0, 0), a = 2, b = 2

Solution steps

8 x^{2} - 15 = 4 y^{2} + 1

Rewrite

8 x^{2} - 15 - 4 y^{2} - 1 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

\frac{x ^{2}}{400} - \frac{y ^{2}}{441} = 1

11 x^{2} - 7 y^{2} + 44 x - 56 y - 145 = 0

25 x^{2} - 64 y^{2} + 100 x - 256 y - 1756 = 0

f (x) f (x) = 3 x^{2} - 4 x - 3

- 81 x^{2} + 486 x + 64 y^{2} + 128 y + 4519 = 0

What is 8x^2-15=4y^2+1 ?
The solution to 8x^2-15=4y^2+1 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=2