What is ((x-6)^2}{16}-\frac{(y-2)^2)/9 =1 ?

The solution to ((x-6)^2}{16}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(6,2),a=4,b=3

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((x-6)^2}{16}-\frac{(y-2)^2)/9 =1

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

(h, k) = (6, 2), a = 4, b = 3

Solution steps

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 6 ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, 2), a = 4, b = 3

\frac{x ^{2}}{33} - \frac{y ^{2}}{3} = 1

x^{2} - 4 x - y^{2} - 6 y - 2 = 0

\frac{( y + 3 ) ^{2}}{64} - \frac{( x + 1 ) ^{2}}{36} = 1

- 4 x^{2} + 9 y^{2} + 24 x - 36 y - 32 = 0

\frac{x ^{2}}{24} - \frac{y ^{2}}{9} = 1

What is ((x-6)^2}{16}-\frac{(y-2)^2)/9 =1 ?
The solution to ((x-6)^2}{16}-\frac{(y-2)^2)/9 =1 is Hyperbola with (h,k)=(6,2),a=4,b=3