What is -16x^2+25y^2-160x-150y-575=0 ?

The solution to -16x^2+25y^2-160x-150y-575=0 is Hyperbola with (h,k)=(-5,3),a=4,b=5

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-16x^2+25y^2-160x-150y-575=0

- 16 x^{2} + 25 y^{2} - 160 x - 150 y - 575 = 0

(h, k) = (- 5, 3), a = 4, b = 5

Solution steps

- 16 x^{2} + 25 y^{2} - 160 x - 150 y - 575 = 0

Rewrite

- 16 x^{2} + 25 y^{2} - 160 x - 150 y - 575 = 0

in the form of a standard hyperbola equation

\frac{( y - 3 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 5 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 3), a = 4, b = 5

x^{2} - y^{2} = \frac{2}{3}

2 x^{2} = 2 y^{2} + 8

x^{2} - y^{2} + 2 x + 2 y - 20 = 0

1 1^{2} + x^{2} = y^{2}

\frac{( x - 5 ) ^{2}}{16} - \frac{( y - 10 ) ^{2}}{10} = 1

What is -16x^2+25y^2-160x-150y-575=0 ?
The solution to -16x^2+25y^2-160x-150y-575=0 is Hyperbola with (h,k)=(-5,3),a=4,b=5