What is ((x-5)^2)/(16)-((y-10)^2)/(10)=1 ?

The solution to ((x-5)^2)/(16)-((y-10)^2)/(10)=1 is Hyperbola with (h,k)=(5,10),a=4,b=sqrt(10)

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((x-5)^2)/(16)-((y-10)^2)/(10)=1

\frac{( x - 5 ) ^{2}}{16} - \frac{( y - 10 ) ^{2}}{10} = 1

(h, k) = (5, 10), a = 4, b = 10

Solution steps

\frac{( x - 5 ) ^{2}}{16} - \frac{( y - 10 ) ^{2}}{10} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{16} - \frac{( y - 10 ) ^{2}}{10} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{4 ^{2}} - \frac{( y - 10 ) ^{2}}{( 10 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 10), a = 4, b = 10

(x - 2)^{2} - (y - 1)^{2} = 4

4 x^{2} - 3 y^{2} + 32 x - 18 y = - 25

4 x^{2} - z^{2} = 1

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 10 ) ^{2}}{36} = 1

\frac{( y - 3 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{9} = 1

What is ((x-5)^2)/(16)-((y-10)^2)/(10)=1 ?
The solution to ((x-5)^2)/(16)-((y-10)^2)/(10)=1 is Hyperbola with (h,k)=(5,10),a=4,b=sqrt(10)