What is ((x-8)/3)^2-((y+3)/4)^2=1 ?

The solution to ((x-8)/3)^2-((y+3)/4)^2=1 is Hyperbola with (h,k)=(8,-3),a=3,b=4

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((x-8)/3)^2-((y+3)/4)^2=1

(\frac{x - 8}{3})^{2} - (\frac{y + 3}{4})^{2} = 1

(h, k) = (8, - 3), a = 3, b = 4

Solution steps

(\frac{x - 8}{3})^{2} - (\frac{y + 3}{4})^{2} = 1

Rewrite

(\frac{x - 8}{3})^{2} - (\frac{y + 3}{4})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 8 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (8, - 3), a = 3, b = 4

\frac{y ^{2}}{20} - x^{2} = 1

9 x^{2} - 4 y^{2} - 36 x + 72 = 0

\frac{z ^{2}}{4} - y^{2} = 1

\frac{( y + 5 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 9

25 y^{2} - x^{2} + 2 x + 150 y + 225 = 0

What is ((x-8)/3)^2-((y+3)/4)^2=1 ?
The solution to ((x-8)/3)^2-((y+3)/4)^2=1 is Hyperbola with (h,k)=(8,-3),a=3,b=4