What is (x^2)/(16)-(y-7)^2=1 ?

The solution to (x^2)/(16)-(y-7)^2=1 is Hyperbola with (h,k)=(0,7),a=4,b=1

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(x^2)/(16)-(y-7)^2=1

\frac{x ^{2}}{16} - (y - 7)^{2} = 1

(h, k) = (0, 7), a = 4, b = 1

Solution steps

\frac{x ^{2}}{16} - (y - 7)^{2} = 1

Rewrite

\frac{x ^{2}}{16} - (y - 7)^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 7 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 7), a = 4, b = 1

x^{2} - 4 x - y^{2} + 4 y - 2 = 0

4 x^{2} - 3 y^{2} + 3 x + 2 y - 3 = 0

- 16 x^{2} + 9 y^{2} - 64 x + 18 y = 199

6 x^{2} - 3 y^{2} - 6 x - 3 y + 78 = 0

- x^{2} + 4 x + 2 y^{2} + 4 y + 2 = 0

What is (x^2)/(16)-(y-7)^2=1 ?
The solution to (x^2)/(16)-(y-7)^2=1 is Hyperbola with (h,k)=(0,7),a=4,b=1