What is (x^2)/(16)-(y^2)/(49)=1 ?

The solution to (x^2)/(16)-(y^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=4,b=7

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(x^2)/(16)-(y^2)/(49)=1

\frac{x ^{2}}{16} - \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 4, b = 7

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 7

(x + 2)^{2} - (y + 2)^{2} = 4^{2}

4 x^{2} - 9 y^{2} - 11 = 0

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y - 2 = 0

\frac{3}{2} (v - \frac{3}{2})^{2} - \frac{1}{2} (u + \frac{3}{2})^{2} = 6

2 x^{2} - 5 y^{2} = 13

What is (x^2)/(16)-(y^2)/(49)=1 ?
The solution to (x^2)/(16)-(y^2)/(49)=1 is Hyperbola with (h,k)=(0,0),a=4,b=7