What is ((y-4)/(16))^2-((x+3)/(36))^2=1 ?

The solution to ((y-4)/(16))^2-((x+3)/(36))^2=1 is Hyperbola with (h,k)=(-3,4),a=16,b=36

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((y-4)/(16))^2-((x+3)/(36))^2=1

(\frac{y - 4}{16})^{2} - (\frac{x + 3}{36})^{2} = 1

(h, k) = (- 3, 4), a = 16, b = 36

Solution steps

(\frac{y - 4}{16})^{2} - (\frac{x + 3}{36})^{2} = 1

Rewrite

(\frac{y - 4}{16})^{2} - (\frac{x + 3}{36})^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{1 6 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{3 6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 4), a = 16, b = 36

\frac{( y - 3 ) ^{2}}{25} - \frac{( x + 4 ) ^{2}}{36} = 1

- 4 x^{2} + y^{2} = 64

y^{2} - 25 x^{2} + 4 y + 50 x - 46 = 0

\frac{y ^{2}}{20} - \frac{x ^{2}}{1} = 1

\frac{( y - 5 ) ^{2}}{16} - (x - 2)^{2} = 1

What is ((y-4)/(16))^2-((x+3)/(36))^2=1 ?
The solution to ((y-4)/(16))^2-((x+3)/(36))^2=1 is Hyperbola with (h,k)=(-3,4),a=16,b=36