What is ((y-4)^2)/(16)-((x+3)^2)/(36)=1 ?

The solution to ((y-4)^2)/(16)-((x+3)^2)/(36)=1 is Hyperbola with (h,k)=(-3,4),a=4,b=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-4)^2)/(16)-((x+3)^2)/(36)=1

\frac{( y - 4 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{36} = 1

(h, k) = (- 3, 4), a = 4, b = 6

Solution steps

\frac{( y - 4 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{36} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{16} - \frac{( x + 3 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 3 ) ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 4), a = 4, b = 6

\frac{y}{4 x ^{2} - 9 y ^{2}} = 36

\frac{( x - 7 ) ^{2}}{16} - \frac{y ^{2}}{9} = 1

16 x^{2} - 32 x = 9 y^{2} + 144 y - 16

y^{(2)} - x^{(2)} = (\frac{1}{49})

9 x^{2} - 4 y^{2} - 72 x + 8 y + 17 = 0

What is ((y-4)^2)/(16)-((x+3)^2)/(36)=1 ?
The solution to ((y-4)^2)/(16)-((x+3)^2)/(36)=1 is Hyperbola with (h,k)=(-3,4),a=4,b=6