What is 4x^2+4(0)^2-z^2=4 ?

The solution to 4x^2+4(0)^2-z^2=4 is Hyperbola with (h,k)=(0,0),a=1,b=2

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4x^2+4(0)^2-z^2=4

4 x^{2} + 4 (0)^{2} - z^{2} = 4

(h, k) = (0, 0), a = 1, b = 2

Solution steps

4 x^{2} + 4 \cdot 0^{2} - z^{2} = 4

Rewrite

4 x^{2} + 4 0^{2} - z^{2} = 4

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( z - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 2

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 1 ) ^{2}}{16} = 1

16 x^{2} - 25 y^{2} + 256 x + 150 y + 399 = 0

y^{2} - x^{2} + y - x - 14 = 0

9 x^{2} - 4 y^{2} - 90 x - 32 y + 125 = 0

\frac{28}{x + y} + \frac{24}{x - y} = 6

What is 4x^2+4(0)^2-z^2=4 ?
The solution to 4x^2+4(0)^2-z^2=4 is Hyperbola with (h,k)=(0,0),a=1,b=2