What is ((x+3)^2)/4-((y+1)^2)/9 =1 ?

The solution to ((x+3)^2)/4-((y+1)^2)/9 =1 is Hyperbola with (h,k)=(-3,-1),a=2,b=3

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((x+3)^2)/4-((y+1)^2)/9 =1

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

(h, k) = (- 3, - 1), a = 2, b = 3

Solution steps

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, - 1), a = 2, b = 3

\frac{( y + 3 ) ^{2}}{81} - \frac{( x + 3 ) ^{2}}{16} = 1

(x - 4)^{2} - (y - 4)^{2} \leq 9

x^{2} + x = y^{2}

\frac{( x ^{(2)} )}{( 9 )} - \frac{( y ^{(2)} )}{( 16 )} = 1

y^{2} - 4 z^{2} = 4

What is ((x+3)^2)/4-((y+1)^2)/9 =1 ?
The solution to ((x+3)^2)/4-((y+1)^2)/9 =1 is Hyperbola with (h,k)=(-3,-1),a=2,b=3