What is (4b-4a)/(b-a)=(a^2-b^2) ?

The solution to (4b-4a)/(b-a)=(a^2-b^2) is Hyperbola with (h,k)=(0,0),a=2,b=2

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(4b-4a)/(b-a)=(a^2-b^2)

\frac{4 b - 4 a}{b - a} = (a^{2} - b^{2})

(h, k) = (0, 0), a = 2, b = 2

Solution steps

\frac{4 b - 4 a}{b - a} = (a^{2} - b^{2})

Rewrite

\frac{4 b - 4 a}{b - a} - a^{2} + b^{2} = 0

in the form of a standard hyperbola equation

\frac{( a - 0 ) ^{2}}{2 ^{2}} - \frac{( b - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

\frac{x ^{2}}{25} - y^{2} = 1

\frac{( x - 3 ) ^{2}}{49} - \frac{( y + 5 ) ^{2}}{25} = 1

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

What is (4b-4a)/(b-a)=(a^2-b^2) ?
The solution to (4b-4a)/(b-a)=(a^2-b^2) is Hyperbola with (h,k)=(0,0),a=2,b=2