What is the vertices ((x-1)^2)/4-((y-2)^2)/1 =1 ?

The vertices ((x-1)^2)/4-((y-2)^2)/1 =1 is (3,2),(-1,2)

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vertices ((x-1)^2)/4-((y-2)^2)/1 =1

vertices

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

(3, 2), (- 1, 2)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1 :

Right-left Hyperbola with

(h, k) = (1, 2), a = 2, b = 1

(1 + 2, 2), (1 - 2, 2)

Refine

(3, 2), (- 1, 2)

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

25 y^{2} - 16 x^{2} - 400 = 0

x^{2} - 9 y^{2} + 4 x + 18 y - 149 = 0

\frac{x ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0

What is the vertices ((x-1)^2)/4-((y-2)^2)/1 =1 ?
The vertices ((x-1)^2)/4-((y-2)^2)/1 =1 is (3,2),(-1,2)