What is the vertices (x^2)/(64)-(y^2)/(36)=1 ?

The vertices (x^2)/(64)-(y^2)/(36)=1 is (8,0),(-8,0)

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vertices (x^2)/(64)-(y^2)/(36)=1

vertices

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

(8, 0), (- 8, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

(0 + 8, 0), (0 - 8, 0)

Refine

(8, 0), (- 8, 0)

x^{2} - \frac{y ^{2}}{4} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{144} = 1

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

What is the vertices (x^2)/(64)-(y^2)/(36)=1 ?
The vertices (x^2)/(64)-(y^2)/(36)=1 is (8,0),(-8,0)