What is the vertices 16x^2-25y^2=400 ?

The vertices 16x^2-25y^2=400 is (5,0),(-5,0)

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vertices 16x^2-25y^2=400

vertices

16 x^{2} - 25 y^{2} = 400

(5, 0), (- 5, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

16 x^{2} - 25 y^{2} = 400 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 4

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

x^{2} - 9 y^{2} - 4 x + 36 y - 41 = 0

\frac{x ^{2}}{9} - \frac{y ^{2}}{49} = 1

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y = 2

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{49} = 1

\frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1

What is the vertices 16x^2-25y^2=400 ?
The vertices 16x^2-25y^2=400 is (5,0),(-5,0)