What is the vertices 4x^2-y^2-24x-4y+28=0 ?

The vertices 4x^2-y^2-24x-4y+28=0 is (4,-2),(2,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 4x^2-y^2-24x-4y+28=0

vertices

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

(4, - 2), (2, - 2)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0 :

Right-left Hyperbola with

(h, k) = (3, - 2), a = 1, b = 2

(3 + 1, - 2), (3 - 1, - 2)

Refine

(4, - 2), (2, - 2)

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

25 x^{2} - 9 y^{2} = 225

3 x^{2} - 15 y^{2} + 2 x - 3 y = 4

What is the vertices 4x^2-y^2-24x-4y+28=0 ?
The vertices 4x^2-y^2-24x-4y+28=0 is (4,-2),(2,-2)